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x^2+36x-205=0
a = 1; b = 36; c = -205;
Δ = b2-4ac
Δ = 362-4·1·(-205)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-46}{2*1}=\frac{-82}{2} =-41 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+46}{2*1}=\frac{10}{2} =5 $
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